Heating 1 kg of lead at 10 ºС consumes 1300 J of heat. Determine the specific heat of lead.
| December 6, 2020 | education
Given: Δt = 10 ° C Q = 1300J m = 1kg
Find: c =?
Q = c * m * Δt => с = Q / m * Δt => С = 1300J / 10ºС * 1kg = 130J / kg * ºС
Answer: the specific heat capacity of lead is 130J / kg * ºС
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