Heating aluminum in a stream of chlorine produced 26.7 AlCl. How many grams of chlorine reacted?

To solve it, you need to compose the reaction equation:
2Al + 3Cl2 = 2AlCl3 – reaction of the compound, aluminum chloride was obtained;
Let’s make calculations using the formulas:
M (Cl2) = 35.5 * 2 = 71 g / mol;
M (AlCl3) = 26.9 + 35.5 * 3 = 133.4 g / mol;
Let’s calculate the amount of mol of aluminum chloride, if the mass is known:
Y (AlCl3) = m / M = 26.7 / 133.4 = 0.2 mol;
Let’s make the proportion:
X mol (Cl2) – 0.2 mol (AlCl3);
-3 mol -2 mol hence, x mol (Cl2) = 3 * 0.2 / 2 = 0.3 mol;
We find the mass of chlorine by the formula:
m (Cl2) = Y * M = 0.3 * 71 = 21.3 g.
Answer: it took 21.3 g of chlorine to carry out the reaction.