Heating ethanol with a mass of 3.45 g with acetic acid with a mass of 3.6 g gave ethyl acetate

Heating ethanol with a mass of 3.45 g with acetic acid with a mass of 3.6 g gave ethyl acetate with a mass of 4.5 g. Determine the yield of ether.

Let’s execute the solution:

According to the condition of the problem, we write down the equation of the process:
С2Н5ОН + СН3СООН = СН3СОО – С2Н5 + Н2О – esterification, ethyl acetate was formed;

We make calculations:
M (C2H5OH) = 46 g / mol;

M (CH3COOH) = 48 g / mol;

M (ethyl acetate) = 88 g / mol.

Determine the number of moles of starting materials:
Y (C2H5OH) = m / M = 3.45 / 46 = 0.075 mol;

Y (CH3COOH) = m / M = 3.6 / 48 = 0.075 mol.

The amounts of starting materials are equal.

We find the ether exit:
m (ethyl acetate) = Y * M = 0.075 * 88 = 6.6 g (theoretical weight);

W = m (practical) / m (theoretical) * 100;

W = 4.5 / 6.6 * 100 = 68.18%

Answer: the yield of ethyl acetate is 68.18%.