Heights CE and AD are drawn in an acute-angled triangle ABC. Prove that triangle ABD is similar to triangle CBE.

Triangles ABD and CBE are rectangular (CE and AD are heights according to the problem statement).
Both one and the second triangle have a common acute angle B. We get the first sign of the similarity of right-angled triangles (for an acute angle). Triangles ABD and CBE are similar, as required.



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