How and how many times does the amount of heat released in the first and second conductors differ?

| February 7, 2021 | education

How and how many times does the amount of heat released in the first and second conductors differ? R1 = 200 Om R2 = 50 Om chain in series

R1 = 200 Ohm.

R2 = 50 Ohm.

Q1 / Q2 -?

The amount of thermal energy Q that is released in the conductor through which the electric current flows is determined by the Joule-Lenz law: Q = I2 * R * t, where I is the current in the conductor, R is the resistance of the conductor, t is the time the current passes through the conductor …

Q1 = I12 * R1 * t1.

Q2 = I22 * R2 * t2.

Since when the conductors are connected in series, they have the same current strength I1 = I2 and the current passage time is also the same t1 = t2.

Q1 / Q2 = I12 * R1 * t1 / I22 * R2 * t2 = R1 / R2.

Q1 / Q2 = 200 ohms / 50 ohms = 4.

Answer: when connected in series, in a conductor with resistance R1, heat energy will be released 4 times more than in resistance R2: Q1 / Q2 = 4.



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