How can iron (III) sulfate be obtained with iron, sulfur, hydrochloric acid and air?

How can iron (III) sulfate be obtained with iron, sulfur, hydrochloric acid and air? Write the equations of the equations of all chemical reactions necessary for a given synthesis, indicating the conditions for their implementation. Consider that for a given synthesis you have any equipment, but are limited by the available reagents.

1) Let’s convert iron to the oxidation state +3 – for this we just heat it well in air: 4Fe + 3O2 = 2Fe2O3
2) Let’s dissolve the oxide in hydrochloric acid, we get iron in ionic form: Fe2O3 + 6HCl = 2FeCl3 + 3H2O. We evaporate the solution, we get solid FeCl3
3) Now we will oxidize sulfur with atmospheric oxygen. The process takes place in two stages, the second – on a catalyst: S + O2 = SO2, 2SO2 + O2 = 2SO3
4) Let’s dissolve the resulting gas in water: SO3 + H2O = H2SO4. Concentrate the resulting acid.
5) On solid iron chloride III, drop a few drops of sulfuric acid: 2FeCl3 + 3H2SO4 = Fe2 (SO4) 3 + 6HCl