How did the value of one of the charges change if the force of interaction increased 1.8

How did the value of one of the charges change if the force of interaction increased 1.8 times, and the distance between the charges decreased 3 times.

Coulomb’s law states that charges interact with each other with a force directly proportional to the magnitude of the charge and inversely proportional to the square of the distance, from the above it follows:
q1 / q2 = (F1 / F2) * (r2 / r1) ^ 2 = 1.8 * 9 = 16.2
One of the charges has increased 16.2 times.



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