How does the oxidation state of carbon change during the combustion of CH4 methane with

How does the oxidation state of carbon change during the combustion of CH4 methane with the formation of carbon monoxide (IV) and water?

Let’s write the chemical reaction equation: C^-4H⁺¹₄ + 2O⁰₂ = C⁺⁴O^-2₂ + 2H⁺¹₂O^-2. The reagents are methane and oxygen, and the reaction products are carbon dioxide and water. As can be seen from the equation of the chemical reaction, carbon in methane (CH4) has an oxidation state of -4, and in carbon dioxide (CO2), the oxidation state of carbon became +4, that is, as a result of a chemical reaction, carbon gave 8 electrons, which means that this chemical element is reducing agent. The oxidizing agent in this chemical reaction is oxygen, which took 4 electrons for two atoms and acquired the oxidation state -2.