How far will a body with a mass of 200 g move in 5 s if it is acted upon by two mutually perpendicular forces of 3H and 4H?

To find the displacement of the specified body, consider the formula: S = 0.5 * a * t ^ 2 = 0.5 * Fr / m * t ^ 2 = 0.5 * t ^ 2 * √ (FA ^ 2 + FB ^ 2 ) / m, where t is the duration of body displacement (t = 5 s); FА – the first acting force (FA = 3 N); FВ – the second acting force (FВ = 4 N); m is the mass of the moving body (m = 200 g = 0.2 kg).

Let’s perform the calculation: S = 0.5 * t ^ 2 * √ (FA ^ 2 + FB ^ 2) / m = 0.5 * 5 ^ 2 * √ (3 ^ 2 + 4 ^ 2) / 0.2 = 312 , 5 m.

Answer: The displacement of the indicated body is 312.5 m.