How fast did you throw the ball up? If the maximum height it has reached is h = 5 …

To solve, you need to understand that Epotential = Ekinetic
Epot = mgh
Ekin = mv ^ 2/2
equating and reducing the mass, we get
gh = v ^ 2/2
we are interested in v
express it
v = √ (2gh)
v = √ (2 * 9.8 * 5) = 9.9 (rounded)
Ball initial speed 9.9 m / s



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