How large is a double-sided diskette if each side contains 40 tracks of 9 sectors

| August 9, 2021 | education

How large is a double-sided diskette if each side contains 40 tracks of 9 sectors, and each sector contains 512 characters from the 256-character alphabet?

1) Find the total number of sectors on one side of the floppy disk.

We multiply the known number of tracks by the specified number of sectors in the track.

40 * 9 = 360 sectors.

2) Determine the number of characters on one side of the floppy disk.

Multiply 360 sectors by 512 characters.

360 * 512 = 184320 characters.

3) Find the number of characters on both sides of the floppy disk.

184320 * 2 = 368640 characters.

4) Determine the information volume of one symbol.

256 = 2 ^ 8

i = 8 bits.

5) Find the volume of all symbols.

368640 * 8 = 2949120 bits.

We translate into Kbytes.

2949120/1024/8 = 359.8 KB.

Answer:

359.8 KB.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.