How long did it take for the trolleybus, moving with an acceleration of 0.2m / s, to increase its speed from 5 to 10m / s?

a = 0.2 m / s2.

V0 = 5 m / s.

V = 10 m / s.

t -?

The acceleration of a trolleybus is called a vector physical quantity that shows how the speed of its movement changes over time t. The trolleybus acceleration a is expressed by the formula: a = (V – V0) / t, where V, V0 are the final and initial speed of its movement, t is the time during which the speed of movement changes.

t = (V – V0) / a.

t = (10 m / s – 5 m / s) / 0.2 m / s2 = 25 s.

Acceleration a = 0.2 m / s2 shows that for every 1 second of movement, the trolleybus speed increases by 0.2 m / s.

Answer: the trolleybus increased its speed in time t = 25 s.