How long does a charge of 10 C pass through the cross section of a conductor, if the current in the conductor

How long does a charge of 10 C pass through the cross section of a conductor, if the current in the conductor is 2 A Determine the number of electrons passing through the cross section of the conductor in 2 s (q0 = 1.6 * 10 (-19 degree) C)

Q = 10 Cl.

I = 2 A.

q0 = 1.6 * 10 ^ -19 Cl.

t1 = 2 s.

t -?

N1 -?

The strength of the current in the conductor I is the ratio of the electric charge Q passed through the cross-section of the conductor to the time of its passage t: I = Q / t.

t = Q / I.

t = 10 C / 2 A = 5 s.

The carriers of an electric charge in conductors are electrons, which have an elementary charge q0 = 1.6 * 10-19 C. The electric charge Q1 can be represented as a product: Q1 = q0 * N1, where N1 is the number of electrons that have passed through the cross section of the conductor.

Q1 = I * t1.

I * t1 = q0 * N1.

N1 = I * t1 / q0.

N1 = 2 A * 2 s / 1.6 * 10 ^ -19 C = 2.5 * 10 ^ 19.

Answer: the charge passed in time t = 5 s, N1 = 2.5 * 10 ^ 19 electrons passed through the cross section of the conductor.