How long does it take for a body, which has begun to fall from rest, to travel 4.9 m?

Since the body began to fall from a state of rest, its initial velocity was v м = 0 m / s. Under the influence of gravity, freely falling bodies move uniformly and rectilinearly, acquiring an acceleration g ≈ 9.8 m / s ^ 2. The path for such a movement is found by the formula h = v₀ ∙ t + g ∙ t² / 2, then:

t = √ (2 ∙ h: g).

From the condition of the problem, it is known that the distance traveled is h = 4.9 m.Let us substitute the values of the quantities in the calculation formula:

t = √ (2 ∙ 4.9 m: 9.8 m / s ^ 2);

t = 1 s.

Answer: in 1 second, the body will pass the intended path.