How long does it take for a car to travel 30m from rest with an acceleration of 0.6 m / s2?

Given:

a = 0.6 m / s ^ 2 – vehicle acceleration;

S = 30 meters – the path traveled by the car.

It is required to determine t (seconds) – the time during which the car covered the path S.

Since, according to the condition of the problem, the car was moving from a state of rest, that is, v0 = 0, then:

t = (2 * S / a) ^ 0.5 = (2 * 30 / 0.6) ^ 0.5 = (60 / 0.6) ^ 0.5 = 100 ^ 0.5 = 10 seconds.

Answer: the car covered the distance of 30 meters in 10 seconds.