How long does it take for the amount of radioactive cesium to decrease 32 times if its half-life is 30 years?
| February 26, 2021 | education
These tasks: m / m0 = N / N0 (decrease in the mass (amount) of radioactive cesium taken) = 32 times; T (half-life) = 30 years.
The time when the amount of taken radioactive cesium decreases by 32 times can be expressed from the formula: m = m0 * 2 ^ -t / T.
m / m0 = 2 ^ -t / T.
32 = 2 ^ -t / 30.
2 ^ 5 = 2 ^ -t / 30.
5 = -t / 30, whence t = 5 * 30 = 150 years.
Answer: The amount of radioactive cesium taken will decrease 32 times in 150 years.
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