How long does it take to coat the item with a layer of silver weighing 447.2 mg at a current of 0.8 A?

How long does it take to coat the item with a layer of silver weighing 447.2 mg at a current of 0.8 A? what charge is transferred? Electrochemical equivalent of silver 1.12 x70 (^ -6)

These tasks: m (weight of the silver layer on the product) = 447.2 mg (447.2 * 10-6 kg); I (current strength during silvering) = 0.8 A.

Reference values: according to the condition k (electrochemical equivalent of silver) = 1.12 * 10-6 kg / C.

The duration of the coating of the product with a layer of silver is determined by the formula (we apply the first Faraday’s law): m = k * I * t, whence t = m / (k * I).

Calculation: t = 447.2 * 10-6 / (1.12 * 10-6 * 0.8) = 499.1 s.

Answer: Coating the item with a layer of silver lasted 499.1 s.