How long is the line, the stiffness of which is 0.5 kn / m, and the elastic force is equal to 2 H?

Given:

k = 0.5 kN / m (kilonewton per meter) – line stiffness coefficient;

F = 2 Newton – elastic force acting on the line.

It is required to determine dx (meter) – how much the line has lengthened under the influence of the force F.

We translate the units of stiffness in the SI system:

k = 0.5 kN / m = 0.5 * 103 = 0.5 * 1000 = 500 N / m.

Then, the extension of the line will be equal to:

dx = F / k = 2/500 = 0.004 meters (4 millimeters).

Answer: The line has lengthened by 4 millimeters.