How long should a 14.7 kW pump work to pump out 150 cm3 of water from a 200m deep mine?

Data: N (pump power) = 14.7 kW (14.7 * 10 ^ 3 W); h (shaft depth) = 200 m; V (volume of pumped water) = 150 cm3 (150 * 10 ^ -6 m3).
Constants: g (acceleration due to gravity) = 9.81 m / s2; ρw (density of pumped water) = 1000 kg / m3.
The duration of the pump operation is determined from the formula for calculating the power: N = A / t = m * g * h / t = ρw * V * g * h / t and t = ρw * V * g * h / N.
Calculation: t = 1000 * 150 * 10 ^ -6 * 9.81 * 200 / (14.7 * 10 ^ 3) = 0.02 s.
Answer: It takes 0.02 s to pump out water.