How long will a fast train 200 m long, traveling at a speed of 66 km / h

How long will a fast train 200 m long, traveling at a speed of 66 km / h, pass a passing freight train 600 m long, traveling at a speed of 30 km / h.

L1 = 200 m.

V1 = 66 km / h = 18.3 m / s.

L2 = 600 m.

V2 = 30 km / h = 8.3 m / s.

tobg -?

Since the trains are moving in the same direction, overtaking will begin from the moment when the first car of the fast train is on the same level with the last car of the freight train. Overtaking will end when the last car of the fast train is on the same level with the first car of the freight train.

The speed of the fast train relative to the freight train V12 will be: V12 = V1 – V2. At this speed, he travels a distance L equal to the length of two trains: L = L1 + L2.

tobg = L / V12 = (L1 + L2) / (V1 – V2).

tobg = (200 m + 600 m) / (18.3 m / s – 8.3 m / s) = 80 s.

Answer: a fast train will overtake a freight train = 80 s.



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