How long will a fishing line with a coefficient of ease of 0.5kN / m lengthen when a fish weighing 250g is lifted vertically upward?

Given:

k = 0.5 kN / m = 500 N / m (Newton per meter) – coefficient of elasticity of the fishing line;

m = 250 grams = 0.25 kilograms – the mass of the fish;

g = 10 N / kg (Newton per kilogram) – acceleration due to gravity (rounded off).

It is required to determine dx (meter) – how much the fishing line will lengthen when the fish is lifted vertically upwards.

Since the problem statement is not specified, we will not take into account any forces other than gravity in the calculation.

Then, the force of gravity acting on the fish will be equal to:

F = m * g = 0.25 * 10 = 2.5 Newton.

The elongation will be equal to:

dx = F / k = 2.5 / 500 = 0.005 meters (5 millimeters).

Answer: when the fish is lifted, the line will lengthen by 5 millimeters.