How long will a stone fall from the Ostankino tower, if its height is 500 m, and the acceleration of the stone is 10 m / s2.

Problem data: h (height of the Ostankino tower, distance covered by the stone) = 500 m; a (acceleration with which the stone fell) = 10 m / s2; the fall of the stone from the tower is considered free (V0 (initial velocity) = 0 m / s).

The duration of the fall of the stone from the Ostankino tower is expressed from the formula: S = h = a * t ^ 2/2, whence t = √ (2h / a).

Calculation: t = √ (2 * 500/10) = 10 s.

Answer: The stone will fall from the Ostankino TV tower for 10 seconds.