How long will it take for body 1 to catch up with body 2 if their velocities are V1 = 12 m / s

How long will it take for body 1 to catch up with body 2 if their velocities are V1 = 12 m / s and V2 = 8 m / s, respectively? The initial distance between the bodies is 200 meters.

When the first body catches up with the second t1 = t2.
t1 = S1 / V1, where S1 is the distance that the first body will travel, V1 is the speed of the first body (V1 = 12 m / s).
t2 = S2 / V2, where S2 is the distance that the second body will travel, V2 is the speed of the second body (V2 = 8 m / s).
S1 = S2 + 200.
S1 / V1 = S2 / V2.
(S2 + 200) / V1 = S2 / V2.
(S2 + 200) / 12 = S2 / 8.
2 * (S2 + 200) / 24 = 3S2 / 24.
2S2 + 400 = 3S2.
S2 = 400 m.
Travel time:
t2 = S2 / V2 = 400/8 = 50 s.
Answer: The first body will catch up with the second in 50 seconds.