How long will it take to stop a 50kg body moving at a speed of 2 m / s with a force of 100N.

univerkov | May 16, 2021 | education

Task data: m (mass of a given body) = 50 kg; V1 (speed before stopping) = 2 m / s; F (force retarding a given body) = 100 N.

1 way) The time it took to stop a given body: t = (V2 – V1) / (-a) = (0 – V1) / (- F / m) = m * V1 / F = 50 * 2/100 = 1 from.

Method 2) Impulse of force: F * t = m * V1 – m * V2 = m * V1 – 0, whence t = m * V1 / F = 1 s.

Answer: It takes 1 second to stop the given body.

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