How long will the body fall from a height of h = 11.25 m?

Body path covered when falling:
S = V0 * t + a * t² / 2, where S is the height of the body falling (S = 11.25 m), V0 is the initial velocity of the body (we assume that the body fell freely without the initial velocity, V0 = 0 m / s) , t – time of the body falling (s), and – body acceleration (а = g (g – gravitational acceleration, g = 10 m / s²)).
S = V0 * t + a * t² / 2 = g * t² / 2.
t = √ (2S / g) = √ (2 * 11.25 / 10) = √ (2.25) = 1.5 s.
Answer: The body will fall within 1.5 seconds.