How long will the rubber cord with a stiffness of 250N / m lengthen under the action of a load whose weight is 5N.

univerkov | December 17, 2020 | education

Given: Force control = 5N Rigidity = 250N / m
Find: ∆l
Solution: Force control: = k∆l => => ∆l = Force control / k => ∆l = 5H / 250 (H / kg) = 0.02m = 2cm
Answer: 2cm

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