m (Al) = 10 g.
Let’s determine the number of aluminum atoms. We write down the solution.
We use the following formula.
N = n * Na.
Where N is the number of atoms.
n is the amount of substance.
Na – Avogardo’s number, constant equal to 6.02 * 10’23.
n = m / M.
Where m is the mass of the substance.
M is the molar mass of the substance.
M (Al) = 27 g / mol.
n (Al) = 10/27 = 0.37 mol
N = 0.37 * 6.02 * 10’23 = 2.22 * 10’23 atoms.
This means that the number of aluminum atoms is 2.22 * 10’23.
Answer: the number of aluminum atoms is 2.22 * 10’23.
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