How many atoms are there in 2050g helium?
| February 26, 2021 | education
Initial data: m (mass of helium) = 2050 g.
Constants: Na (Avogadro’s number) = 6.02 * 10 ^ 23 mol-1; M (molar mass of helium) ≈ 4 g / mol.
The number of atoms contained in 2050 grams of helium is determined from the equality: m / M = ν = N / Na, whence N = m * Na / M.
Calculation: N = 2050 * 6.02 * 10 ^ 23/4 = 3085.25 * 10 ^ 23 atoms.
Answer: 2050 grams of helium contains 3085.25 * 10 ^ 23 atoms.
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