How many atoms are there in 3.2 g of oxygen O2?
| August 5, 2021 | education
m (O2) = 3.2 g.
Let’s determine the number of oxygen atoms. We write down the solution.
We use the following formula.
N = n * Na.
Where N is the number of atoms.
n is the amount of substance.
Na – Avogardo’s number equal to 6.02 * 10’23
We find the amount of substance.
n = m / M.
M (O2) = 16 * 2 = 32 g / mol.
M (O2) = 3.2 / 32 = 0.1 mol.
N (O2) = 0.1 * 6.02 * 10’23 = 0.602 * 10’23 = 6.02 * 10’22 atoms.
This means that 3.2 grams of oxygen contains 6.02 * 10’22 atoms.
Answer: N (O2) = 6.02 * 10’22 atoms.
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