How many atoms do helium gas contain with a mass of m = 1 g?

univerkov | March 23, 2021 | education

Problem data: m (mass of taken helium) = 1 g.

Reference values: M (molar mass of helium) ≈ 4 g / mol (0.004 kg / mol); Na (Avogadro’s number) = 6.02 * 10 ^ 23 mol-1.

The required number of atoms, which is contained in 1 gram of helium, can be expressed from the equality: m / M = ν (amount of helium substance) = N / Na, whence N = m * Na / M.

Let’s make a calculation: N = 1 * 6.02 / 4 = 1.505 * 10 ^ 23 atoms.

Answer: 1 gram of helium contains 1.505 * 10 ^ 23 atoms.

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