How many bits of information does a 64 megabyte message contain?
| December 12, 2020 | education
64 = 2 ^ 6
8 = 2 ^ 3
1024 = 2 ^ 10
Hence:
64 mb = 2 ^ 6 + 2 ^ 10 = 2 ^ 16 kb = 2 ^ 16 + 2 ^ 10 = 2 ^ 26 bytes = 2 ^ 26 + 2 ^ 3 = 2 ^ 29 bits
2 ^ 29 bits = 536870912 bits
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