How many cars can an electric locomotive carry uniformly along a horizontal track, the traction force

How many cars can an electric locomotive carry uniformly along a horizontal track, the traction force of which is 13 940 N, if the mass of the electric locomotive is 184 tons, the mass of one car is 55 tons, and the rolling friction coefficient is 0.001?

Given: the electric locomotive moves uniformly (V = const); F (traction force of the electric locomotive) = 13940 N; m1 (mass of an electric locomotive) = 184 t (184 * 10 ^ 3 kg); m2 (wagon weight) = 55 t (55 * 10 ^ 3 kg); μ (rolling friction coefficient) = 0.001.

Reference data: g (acceleration due to gravity) ≈ 10 m / s2.

The number of cars is determined from the formula: F = Ftr. = μ * N = μ * m * g = μ * (m1 + m2 * n) * g, whence m1 + m2 * n = F / (μ * g) and n = (F / (μ * g) – m1 ) / m2.

Calculation: n = (13940 / (0.001 * 10) – 184 * 10 ^ 3) / (55 * 10 ^ 3) = 22.



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