How many cars will be required to transport 56 tons of potatoes, If the volume of the body is 4 m3?

How many cars will be required to transport 56 tons of potatoes, If the volume of the body is 4 m3? The density of the potatoes should be taken equal to 700 kg / m3.

First, we find the entire volume of potatoes. The mass of the potato is m = 56 tons. Using the equality 1 t = 1000 kg, we express the mass of the potato in kilograms: m = 56 tons = (56 * 1000) kg = 56000 kg. We use the formula V = m / ρ, where V is the volume of a homogeneous body (in m³), m is its mass (in kg), ρ is its density (in kg / m³). The task gives the density of potatoes ρ = 700 kg / m³. Therefore, V = (56000 kg) / (700 kg / m³) = 80 m³. Since the volume of the body is 4 m³, the required number of cars is (80 m³): (4 m³) = 20.