How many centimeters will a spring with a stiffness of 100N / m stretch if you hang a weight of 200g to it?

To find out the required tension (deformation) of the used spring, consider the equality: Fel = -k * Δlx = mg * g = Ft, from where we express: Δlx = mg * g / k.

Const: g – acceleration due to gravity (g ≈ 9.81 m / s2).

Data: mg is the weight of the suspended weight (mg = 200 g; in the SI system, mg = 0.2 kg); k is the stiffness of the spring used (k = 100 N / m).

Calculation: Δlx = mg * g / k = 0.2 * 9.81 / 100 = 0.01962 m ≈ 2 cm.

Answer: After hanging the weight, the spring used should stretch 2 cm.