How many CuSO4 5H2O scars should be taken to prepare 300 gr of 5 percent solution calculated for anhydrous salt

Given:
m solution (CuSO4) = 300 g
ω (CuSO4) = 5%

Find:
m (CuSO4 * 5H2O) -?

Solution:
1) Calculate the mass of CuSO4:
m (CuSO4) = ω (CuSO4) * m solution (CuSO4) / 100% = 5% * 300/100% = 15 g;
2) Calculate the molar masses of CuSO4 and CuSO4 * 5H2O:
M (CuSO4) = 160 g / mol;
M (CuSO4 * 5H2O) = 250 g / mol;
3) Calculate the amount of substance CuSO4:
n (CuSO4) = m (CuSO4) / M (CuSO4) = 15/160 = 0.1 mol;
4) Determine the amount of substance CuSO4 * 5H2O:
n (CuSO4 * 5H2O) = n (CuSO4) = 0.1 mol;
5) Calculate the mass of CuSO4 * 5H2O:
m (CuSO4 * 5H2O) = n (CuSO4 * 5H2O) * M (CuSO4 * 5H2O) = 0.1 * 250 = 25 g.

Answer: The mass of CuSO4 * 5H2O is 25 g.