How many degrees can you heat water weighing 2 kg if you burn 8.4 g of alcohol?

univerkov | May 9, 2021 | education

Data: m1 (mass of alcohol burnt) = 8.4 g (8.4 * 10 ^ -3 kg); m2 (mass of water) = 2 kg.

Reference values: q (specific heat of combustion of alcohol) = 2.7 * 10 ^ 7 J / kg; С (specific heat capacity of water) = 4200 J / (kg * ºС).

1) The heat that will be released during combustion of 8.4 g of alcohol: Q = q * m1 = 2.7 * 10 ^ 7 * 8.4 * 10 ^ -3 = 226800 J.

2) Change in temperature of 2 kg of water: Δt = Q / (C * m ^ 2) = 226800 / (4200 * 2) = 27 ºC.

Answer: The water can be heated to 27 ºC.

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