How many degrees can you heat water with a mass of 11 kg, when burning kerosene with a mass of 20 g

How many degrees can you heat water with a mass of 11 kg, when burning kerosene with a mass of 20 g, if we assume that the heat released during combustion went entirely to heating the water?

Data: m1 (mass of water) = 11 kg; m2 (mass of kerosene burned) = 20 g (0.02 kg); the heat from the combustion of kerosene will be used to heat water without losses.

Constants: C1 (specific heat capacity of water) = 4200 J / (kg * ºС); q (specific heat of combustion of kerosene) = 4.6 * 10 ^ 7 J / kg.

1) The heat released from the combustion of 20 g of kerosene: Q = q * m2 = 4.6 * 10 ^ 7 * 0.02 = 920000 J.

2) Change in temperature of 11 kg of water: Δt1 = Q / (C1 * m1) = 920000 / (4200 * 11) = 19.9 ºС.

Answer: The water can be heated up to 19.9 ºС.



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