How many degrees can you heat water with a mass of 5.5 kg, if the amount of heat released during the combustion

How many degrees can you heat water with a mass of 5.5 kg, if the amount of heat released during the combustion of 20 g of kerosene goes entirely to heat it?

Given:

m = 5.5 kilograms is the mass of water;

s = 4200 J / (kg * C) – specific heat capacity of water;

m1 = 20 grams = 0.02 kilograms is the mass of kerosene;

q = 40.8 * 10 ^ 6 J / kg – specific heat of combustion of kerosene.

It is required to determine dt (degree Celsius) – how many degrees the water will heat up, with the complete combustion of kerosene with a mass of m1.

Let’s find the amount of heat that will be released during the complete combustion of kerosene:

Q = m1 * q = 0.02 * 40.8 * 10 ^ 6 = 0.816 * 10 ^ 6 Joules.

Then, the temperature will be equal to:

dt = Q / (c * m) = 0.816 * 10 ^ 6 / (4200 * 5.5) = 0.816 * 10 ^ 6/23100 = 816000/23100 = 35 ° Celsius.

Answer: The water temperature will increase by 35 ° Celsius.