How many degrees can you heat water with a mass of 8 kg when burning gasoline with a mass of 60
How many degrees can you heat water with a mass of 8 kg when burning gasoline with a mass of 60 grams, if the heating efficiency is 80%.
Given:
m1 = 60 grams = 0.06 kilograms – the mass of gasoline;
m2 = 8 kilograms – the mass of water;
q = 44 * 10 ^ 6 J / kg – specific heat of combustion of gasoline;
c = 4183 J / (kg deg) – specific heat capacity of water;
n = 80% = 0.8 – combustion efficiency.
It is required to determine how many degrees dT (Celsius) water of mass m2 will be heated when gasoline with mass m1 is burned.
When gasoline burns, heat energy is released:
Q = q * m1 = 44 * 10 ^ 6 * 0.06 = 2.64 * 10 ^ 6 Joules.
This energy will be used to heat water:
Q1 = n * Q = 2.64 * 10 ^ 6 * 0.8 = 2.1 * 10 ^ 6 Joules.
Due to this energy, water can be heated:
dT = Q1 / (c * m2) = 2.1 * 10 ^ 6 / (8 * 4183) = 2.1 * 10 ^ 6/33464 = 62.8 degrees Celsius.
Answer: when burning gasoline, you can heat the water to 62.8 degrees Celsius.
