# How many degrees can you heat water with a volume of 10 liters, using all the heat released

How many degrees can you heat water with a volume of 10 liters, using all the heat released during the combustion of kerosene, whose mass is 21 g?

Given: V1 (water volume) = 10 l (10 * 10 ^ -3 m3); m2 (mass of burned kerosene) = 21 g (0.012 kg).

Constants: ρ (density of heated water) = 1000 kg / m3; C1 (heat capacity of water) = 4200 J / (kg * ºС); q (heat of combustion of kerosene) = 46 * 10 ^ 6 J / kg.

1) Heat from combustion of 21 g of kerosene: Q = q * m2 = 46 * 10 ^ 6 * 0.021 = 0.966 * 10 ^ 6 J.

2) Change in water temperature: Δt1 = Q / (C1 * m1) = Q / (C1 * ρ * V1) = 0.966 * 10 ^ 6 / (4200 * 1000 * 10 * 10 ^ -3) = 23 ºС.

Answer: Water with a volume of 10 liters can be heated by 23 ºС.

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