How many degrees Celsius will 3 kg of water heat up if all the heat released during the complete combustion

How many degrees Celsius will 3 kg of water heat up if all the heat released during the complete combustion of 10 g of alcohol went to heat it? The specific heat of combustion of alcohol is 27 MJ / kg.

Here is given in the SI system:
mс = 10g = 0.01 kg.
q = 27 MJ / kg = 27 * 10 ^ 6 J.
1. The amount of heat released during the combustion of alcohol:
Q = q * mс, where q is the specific heat of combustion, m is the mass of the fuel.
2. The amount of heat spent on heating the body is equal to the product of the specific heat capacity of the substance, body weight and the difference between the final and initial temperatures.
Q = c * mw * (t2-t1), where c is the specific heat capacity of the substance, m is the mass of the substance, t2 and t1 are the final and initial temperatures, respectively.
Specific heat of water c = 4200 J / kg * K, according to the reference book.
3. Since all the heat was used to heat the water:
q * mc = c * mw * (t2-t1)
Let us express from this expression (t2-t1):
(t2-t1) = q * mc / (c * mb)
substitute the numerical values:
(t2-t1) = q * mc / (c * mb) = 27 * 10 ^ 6 * 0.01 / (4200 * 3) = 21.4 ° C
Answer: The water will heat up to 21.4 ° C.