How many degrees did the ether with a mass of 1.6 kg heat up if 131.6 kJ of heat was transferred to it?

Formula that we will use: Q = cm (t2- t1)
Need to find (t2- t1)
Then (t2- t1) = Q / (cm)
Heat capacity of ether c = 3340 J / kg * K
(t2- t1) = 131600 / (3340 * 1.6) = 24.63 degrees



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