How many degrees did the temperature of 4 liters of water rise if it received an amount of heat equal to 168 kJ.
| January 12, 2021 | education
The change in water temperature can be calculated from the formula for heating bodies:
Q = C * m * Δt, where Q is the heat imparted to the water (Q = 168 kJ = 168 * 10 ^ 3 J), C is the specific heat capacity (tabular value, for water C = 4200 J / (kg * K) ), m is the mass of water (water weighing 4 kg has a volume equal to 4 liters), Δt is the change in water temperature.
Δt = Q / (C * m).
Let’s do the calculation:
Δt = 168 * 10 ^ 3 / (4200 * 4) = 10 ºС.
Answer: The water temperature has increased by 10 ºС.
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