How many degrees did the temperature of 5 liters of water rise if it received 200 kJ of heat?

To find the answer to the question of the problem, we will start with a short entry given:

V (H20) = 5 liters;

Q = 200 kJ.

To find:

how much the water temperature has risen.

Decision:

To calculate how many degrees the temperature of 5 liters of water has risen, we will apply a formula to calculate the amount of heat. Let’s remember the formula:

Q = c * m * dt, Let us express the temperature difference:

dt = Q / (c * m).

It is known that the density of water is 1000 kg / m³, we conclude that 1 liter = 1 kg.

That is, 5 liters of water is 5 kg of water.

c – const, specific heat capacity of a substance, for water this value is 4 200 J / (kg * K).

Substitute the values ​​and calculate:

dt = 200,000 / 4,200 * 5 = 9.5 °.