How many degrees does 40 grams of ice cool if it gives off an amount of heat of 500 J.

univerkov | September 21, 2021 | education

Problem data: m (mass of cooled ice) = 40 g (in SI m = 0.04 kg); Q (the amount of heat given off by the taken ice) = 500 J.

Reference values: Сl (specific heat capacity of ice) = 2100 J / (kg * K).

The change in the temperature of the taken ice during cooling can be expressed from the formula: Q = Сl * m * Δt, whence Δt = Q / (Сl * m).

Calculation: Δt = 500 / (2100 * 0.04) = 5.95 ºС.

Answer: The ice will be able to cool down by 5.95 ºС.

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