How many degrees does an iron iron weighing 2 kg heat up if 73.6 kJ of heat is transferred to it

How many degrees does an iron iron weighing 2 kg heat up if 73.6 kJ of heat is transferred to it, the specific heat of iron is 460 J / kg C

Given:

m = 2 kg

Q = 73.6 kJ

c = 460 J / kg * C

Find: t2 – t1.

Let’s write down the formula for the amount of heat.

Q = c * m * (t2 – t1).

From this formula, we write down what the temperature difference is equal to.

t2 – t1 = Q / m * c

Let’s give the units of measurement of all data in the SI system.

Q = 73.6 kJ = 73600 J

Let’s find the temperature difference.

t2 – t1 = 73600/460 = 160 ° C.

Let us express the temperature difference in Kelvin.

160 ° C + 273 = 433 K.
Answer: The iron iron will heat up to 160 ° C., Or 433 Kelvin