How many degrees does the temperature of hot water with a volume of 30 liters increase if it receives 1500 kJ of heat?
| June 17, 2021 | education
Task data: V (volume of hot water taken) = 30 l (30 * 10 ^ -3 m3); Q (the amount of heat that hot water received) = 1500 kJ (1500 * 10 ^ 3 J).
Constants: Sv (specific heat of water) = 4200 J / (kg * K); ρ (water density) = 1000 kg / m3.
The increase in hot water temperature can be expressed from the formula: Q = Sv * m * Δt = Sv * ρ * V * Δt, whence Δt = Q / (Sv * ρ * V).
Calculation: Δt = 1500 * 10 ^ 3 / (4200 * 1000 * 30 * 10 ^ -3) = 11.9 ºС.
Answer: The hot water temperature will increase by 11.9 ºС.
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