How many degrees has the boiling water with a mass of 27 kg cooled down if it has given 1500 J

How many degrees has the boiling water with a mass of 27 kg cooled down if it has given 1500 J of heat to the environment?

We use the formula for calculations: Q = cm (t0 – t)

We denote what needs to be found by T

T = t0 – t

Given:

Q = 1500 J

m = 27 kg

c = 4200 J / kg * OS

We get the formula: Q = cmT
We express T
T = Q / cm

Substituting numeric values
T = 1500/4200 * 27

T = 0.013 oC

It is possible that an error was made in the condition and the units of measurement are not J, but kJ.

Then:

T = 1500000/4200 * 27

T = 13 OC

Answer: 0.013 or 13 degrees Celsius.



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