How many degrees ice with a mass of 40 g will be cooled, if at the same time a stake of heat equal to 450 kJ is released.

Initial data: m (ice mass) = 40 kg; Q (the amount of heat released when ice is cooled) = 450 kJ = 450 * 10 ^ 3 J.

Reference data: C (specific heat capacity of ice) = 2100 J / (kg * K).

The change in ice temperature during cooling can be expressed from the formula: Q = C * m * Δt, whence Δt = Q / (C * m).

Let’s make a calculation: Δt = 450 * 10 ^ 3 / (2100 * 40) = 5.36 ºС.

Answer: The ice will cool down by 5.36 ºС.



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