How many degrees in 5 minutes does a copper electric soldering iron weighing 480 grams, connected

How many degrees in 5 minutes does a copper electric soldering iron weighing 480 grams, connected to the network with a voltage of 120 volts at a current of 2.5 A, heat up?

According to the Joule-Lenz law, the amount of heat on the soldering iron:
Q = I * U * t, where I is the current strength (I = 2.5 A), U is the voltage in the network (U = 120 V), t is the current flow time (t = 5 min = 5 * 60 = 300 with)
The released heat is used for heating:
Q = C * m * ∆t, where C is the specific heat capacity of copper (C = 385 J / (kg * K)), m is the mass of the soldering iron (m = 480 g = 0.48 kg), ∆t is the temperature change ( TO).
Hence:
I * U * t = C * m * ∆t.
∆t = I * U * t / (C * m) = 2.5 * 120 * 300 / (385 * 0.48) = 487 K.
Answer. The electric soldering iron will heat up to 487 K.